3.1.89 \(\int \frac {(d+c d x)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx\) [89]

3.1.89.1 Optimal result
3.1.89.2 Mathematica [C] (verified)
3.1.89.3 Rubi [A] (verified)
3.1.89.4 Maple [C] (warning: unable to verify)
3.1.89.5 Fricas [F]
3.1.89.6 Sympy [F]
3.1.89.7 Maxima [F]
3.1.89.8 Giac [F]
3.1.89.9 Mupad [F(-1)]

3.1.89.1 Optimal result

Integrand size = 22, antiderivative size = 361 \[ \int \frac {(d+c d x)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx=a b c^2 d^3 x+b^2 c^2 d^3 x \text {arctanh}(c x)+\frac {7}{2} c d^3 (a+b \text {arctanh}(c x))^2-\frac {d^3 (a+b \text {arctanh}(c x))^2}{x}+3 c^2 d^3 x (a+b \text {arctanh}(c x))^2+\frac {1}{2} c^3 d^3 x^2 (a+b \text {arctanh}(c x))^2+6 c d^3 (a+b \text {arctanh}(c x))^2 \text {arctanh}\left (1-\frac {2}{1-c x}\right )-6 b c d^3 (a+b \text {arctanh}(c x)) \log \left (\frac {2}{1-c x}\right )+\frac {1}{2} b^2 c d^3 \log \left (1-c^2 x^2\right )+2 b c d^3 (a+b \text {arctanh}(c x)) \log \left (2-\frac {2}{1+c x}\right )-3 b^2 c d^3 \operatorname {PolyLog}\left (2,1-\frac {2}{1-c x}\right )-3 b c d^3 (a+b \text {arctanh}(c x)) \operatorname {PolyLog}\left (2,1-\frac {2}{1-c x}\right )+3 b c d^3 (a+b \text {arctanh}(c x)) \operatorname {PolyLog}\left (2,-1+\frac {2}{1-c x}\right )-b^2 c d^3 \operatorname {PolyLog}\left (2,-1+\frac {2}{1+c x}\right )+\frac {3}{2} b^2 c d^3 \operatorname {PolyLog}\left (3,1-\frac {2}{1-c x}\right )-\frac {3}{2} b^2 c d^3 \operatorname {PolyLog}\left (3,-1+\frac {2}{1-c x}\right ) \]

output
a*b*c^2*d^3*x+b^2*c^2*d^3*x*arctanh(c*x)+7/2*c*d^3*(a+b*arctanh(c*x))^2-d^ 
3*(a+b*arctanh(c*x))^2/x+3*c^2*d^3*x*(a+b*arctanh(c*x))^2+1/2*c^3*d^3*x^2* 
(a+b*arctanh(c*x))^2-6*c*d^3*(a+b*arctanh(c*x))^2*arctanh(-1+2/(-c*x+1))-6 
*b*c*d^3*(a+b*arctanh(c*x))*ln(2/(-c*x+1))+1/2*b^2*c*d^3*ln(-c^2*x^2+1)+2* 
b*c*d^3*(a+b*arctanh(c*x))*ln(2-2/(c*x+1))-3*b^2*c*d^3*polylog(2,1-2/(-c*x 
+1))-3*b*c*d^3*(a+b*arctanh(c*x))*polylog(2,1-2/(-c*x+1))+3*b*c*d^3*(a+b*a 
rctanh(c*x))*polylog(2,-1+2/(-c*x+1))-b^2*c*d^3*polylog(2,-1+2/(c*x+1))+3/ 
2*b^2*c*d^3*polylog(3,1-2/(-c*x+1))-3/2*b^2*c*d^3*polylog(3,-1+2/(-c*x+1))
 
3.1.89.2 Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 0.50 (sec) , antiderivative size = 479, normalized size of antiderivative = 1.33 \[ \int \frac {(d+c d x)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx=\frac {d^3 \left (-8 a^2+i b^2 c \pi ^3 x+24 a^2 c^2 x^2+8 a b c^2 x^2+4 a^2 c^3 x^3-16 a b \text {arctanh}(c x)+48 a b c^2 x^2 \text {arctanh}(c x)+8 b^2 c^2 x^2 \text {arctanh}(c x)+8 a b c^3 x^3 \text {arctanh}(c x)-8 b^2 \text {arctanh}(c x)^2-20 b^2 c x \text {arctanh}(c x)^2+24 b^2 c^2 x^2 \text {arctanh}(c x)^2+4 b^2 c^3 x^3 \text {arctanh}(c x)^2-16 b^2 c x \text {arctanh}(c x)^3+16 b^2 c x \text {arctanh}(c x) \log \left (1-e^{-2 \text {arctanh}(c x)}\right )-48 b^2 c x \text {arctanh}(c x) \log \left (1+e^{-2 \text {arctanh}(c x)}\right )-24 b^2 c x \text {arctanh}(c x)^2 \log \left (1+e^{-2 \text {arctanh}(c x)}\right )+24 b^2 c x \text {arctanh}(c x)^2 \log \left (1-e^{2 \text {arctanh}(c x)}\right )+24 a^2 c x \log (x)+16 a b c x \log (c x)+4 a b c x \log (1-c x)-4 a b c x \log (1+c x)+16 a b c x \log \left (1-c^2 x^2\right )+4 b^2 c x \log \left (1-c^2 x^2\right )+24 b^2 c x (1+\text {arctanh}(c x)) \operatorname {PolyLog}\left (2,-e^{-2 \text {arctanh}(c x)}\right )-8 b^2 c x \operatorname {PolyLog}\left (2,e^{-2 \text {arctanh}(c x)}\right )+24 b^2 c x \text {arctanh}(c x) \operatorname {PolyLog}\left (2,e^{2 \text {arctanh}(c x)}\right )-24 a b c x \operatorname {PolyLog}(2,-c x)+24 a b c x \operatorname {PolyLog}(2,c x)+12 b^2 c x \operatorname {PolyLog}\left (3,-e^{-2 \text {arctanh}(c x)}\right )-12 b^2 c x \operatorname {PolyLog}\left (3,e^{2 \text {arctanh}(c x)}\right )\right )}{8 x} \]

input
Integrate[((d + c*d*x)^3*(a + b*ArcTanh[c*x])^2)/x^2,x]
 
output
(d^3*(-8*a^2 + I*b^2*c*Pi^3*x + 24*a^2*c^2*x^2 + 8*a*b*c^2*x^2 + 4*a^2*c^3 
*x^3 - 16*a*b*ArcTanh[c*x] + 48*a*b*c^2*x^2*ArcTanh[c*x] + 8*b^2*c^2*x^2*A 
rcTanh[c*x] + 8*a*b*c^3*x^3*ArcTanh[c*x] - 8*b^2*ArcTanh[c*x]^2 - 20*b^2*c 
*x*ArcTanh[c*x]^2 + 24*b^2*c^2*x^2*ArcTanh[c*x]^2 + 4*b^2*c^3*x^3*ArcTanh[ 
c*x]^2 - 16*b^2*c*x*ArcTanh[c*x]^3 + 16*b^2*c*x*ArcTanh[c*x]*Log[1 - E^(-2 
*ArcTanh[c*x])] - 48*b^2*c*x*ArcTanh[c*x]*Log[1 + E^(-2*ArcTanh[c*x])] - 2 
4*b^2*c*x*ArcTanh[c*x]^2*Log[1 + E^(-2*ArcTanh[c*x])] + 24*b^2*c*x*ArcTanh 
[c*x]^2*Log[1 - E^(2*ArcTanh[c*x])] + 24*a^2*c*x*Log[x] + 16*a*b*c*x*Log[c 
*x] + 4*a*b*c*x*Log[1 - c*x] - 4*a*b*c*x*Log[1 + c*x] + 16*a*b*c*x*Log[1 - 
 c^2*x^2] + 4*b^2*c*x*Log[1 - c^2*x^2] + 24*b^2*c*x*(1 + ArcTanh[c*x])*Pol 
yLog[2, -E^(-2*ArcTanh[c*x])] - 8*b^2*c*x*PolyLog[2, E^(-2*ArcTanh[c*x])] 
+ 24*b^2*c*x*ArcTanh[c*x]*PolyLog[2, E^(2*ArcTanh[c*x])] - 24*a*b*c*x*Poly 
Log[2, -(c*x)] + 24*a*b*c*x*PolyLog[2, c*x] + 12*b^2*c*x*PolyLog[3, -E^(-2 
*ArcTanh[c*x])] - 12*b^2*c*x*PolyLog[3, E^(2*ArcTanh[c*x])]))/(8*x)
 
3.1.89.3 Rubi [A] (verified)

Time = 1.04 (sec) , antiderivative size = 361, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {6502, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(c d x+d)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx\)

\(\Big \downarrow \) 6502

\(\displaystyle \int \left (c^3 d^3 x (a+b \text {arctanh}(c x))^2+3 c^2 d^3 (a+b \text {arctanh}(c x))^2+\frac {d^3 (a+b \text {arctanh}(c x))^2}{x^2}+\frac {3 c d^3 (a+b \text {arctanh}(c x))^2}{x}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {1}{2} c^3 d^3 x^2 (a+b \text {arctanh}(c x))^2+3 c^2 d^3 x (a+b \text {arctanh}(c x))^2-3 b c d^3 \operatorname {PolyLog}\left (2,1-\frac {2}{1-c x}\right ) (a+b \text {arctanh}(c x))+3 b c d^3 \operatorname {PolyLog}\left (2,\frac {2}{1-c x}-1\right ) (a+b \text {arctanh}(c x))+\frac {7}{2} c d^3 (a+b \text {arctanh}(c x))^2-\frac {d^3 (a+b \text {arctanh}(c x))^2}{x}+6 c d^3 \text {arctanh}\left (1-\frac {2}{1-c x}\right ) (a+b \text {arctanh}(c x))^2-6 b c d^3 \log \left (\frac {2}{1-c x}\right ) (a+b \text {arctanh}(c x))+2 b c d^3 \log \left (2-\frac {2}{c x+1}\right ) (a+b \text {arctanh}(c x))+a b c^2 d^3 x+b^2 c^2 d^3 x \text {arctanh}(c x)+\frac {1}{2} b^2 c d^3 \log \left (1-c^2 x^2\right )-3 b^2 c d^3 \operatorname {PolyLog}\left (2,1-\frac {2}{1-c x}\right )-b^2 c d^3 \operatorname {PolyLog}\left (2,\frac {2}{c x+1}-1\right )+\frac {3}{2} b^2 c d^3 \operatorname {PolyLog}\left (3,1-\frac {2}{1-c x}\right )-\frac {3}{2} b^2 c d^3 \operatorname {PolyLog}\left (3,\frac {2}{1-c x}-1\right )\)

input
Int[((d + c*d*x)^3*(a + b*ArcTanh[c*x])^2)/x^2,x]
 
output
a*b*c^2*d^3*x + b^2*c^2*d^3*x*ArcTanh[c*x] + (7*c*d^3*(a + b*ArcTanh[c*x]) 
^2)/2 - (d^3*(a + b*ArcTanh[c*x])^2)/x + 3*c^2*d^3*x*(a + b*ArcTanh[c*x])^ 
2 + (c^3*d^3*x^2*(a + b*ArcTanh[c*x])^2)/2 + 6*c*d^3*(a + b*ArcTanh[c*x])^ 
2*ArcTanh[1 - 2/(1 - c*x)] - 6*b*c*d^3*(a + b*ArcTanh[c*x])*Log[2/(1 - c*x 
)] + (b^2*c*d^3*Log[1 - c^2*x^2])/2 + 2*b*c*d^3*(a + b*ArcTanh[c*x])*Log[2 
 - 2/(1 + c*x)] - 3*b^2*c*d^3*PolyLog[2, 1 - 2/(1 - c*x)] - 3*b*c*d^3*(a + 
 b*ArcTanh[c*x])*PolyLog[2, 1 - 2/(1 - c*x)] + 3*b*c*d^3*(a + b*ArcTanh[c* 
x])*PolyLog[2, -1 + 2/(1 - c*x)] - b^2*c*d^3*PolyLog[2, -1 + 2/(1 + c*x)] 
+ (3*b^2*c*d^3*PolyLog[3, 1 - 2/(1 - c*x)])/2 - (3*b^2*c*d^3*PolyLog[3, -1 
 + 2/(1 - c*x)])/2
 

3.1.89.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 6502
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*((f_.)*(x_))^(m_.)*((d_) + (e 
_.)*(x_))^(q_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*ArcTanh[c*x])^p, ( 
f*x)^m*(d + e*x)^q, x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && IGtQ[p, 0] 
 && IntegerQ[q] && (GtQ[q, 0] || NeQ[a, 0] || IntegerQ[m])
 
3.1.89.4 Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 9.07 (sec) , antiderivative size = 1012, normalized size of antiderivative = 2.80

method result size
parts \(\text {Expression too large to display}\) \(1012\)
derivativedivides \(\text {Expression too large to display}\) \(1014\)
default \(\text {Expression too large to display}\) \(1014\)

input
int((c*d*x+d)^3*(a+b*arctanh(c*x))^2/x^2,x,method=_RETURNVERBOSE)
 
output
d^3*a^2*(1/2*c^3*x^2+3*c^2*x-1/x+3*c*ln(x))+d^3*b^2*c*(3*c*x*arctanh(c*x)^ 
2-6*dilog(1+I*(c*x+1)/(-c^2*x^2+1)^(1/2))-6*dilog(1-I*(c*x+1)/(-c^2*x^2+1) 
^(1/2))+1/2*c^2*x^2*arctanh(c*x)^2+2*dilog(1+(c*x+1)/(-c^2*x^2+1)^(1/2))+3 
/2*arctanh(c*x)^2-1/c/x*arctanh(c*x)^2-ln(1+(c*x+1)^2/(-c^2*x^2+1))-2*dilo 
g((c*x+1)/(-c^2*x^2+1)^(1/2))-6*arctanh(c*x)*ln(1+I*(c*x+1)/(-c^2*x^2+1)^( 
1/2))-6*arctanh(c*x)*ln(1-I*(c*x+1)/(-c^2*x^2+1)^(1/2))+3/2*polylog(3,-(c* 
x+1)^2/(-c^2*x^2+1))-6*polylog(3,-(c*x+1)/(-c^2*x^2+1)^(1/2))-6*polylog(3, 
(c*x+1)/(-c^2*x^2+1)^(1/2))+3*ln(c*x)*arctanh(c*x)^2-3*arctanh(c*x)*polylo 
g(2,-(c*x+1)^2/(-c^2*x^2+1))-3*arctanh(c*x)^2*ln((c*x+1)^2/(-c^2*x^2+1)-1) 
+3*arctanh(c*x)^2*ln(1+(c*x+1)/(-c^2*x^2+1)^(1/2))+6*arctanh(c*x)*polylog( 
2,-(c*x+1)/(-c^2*x^2+1)^(1/2))+3*arctanh(c*x)^2*ln(1-(c*x+1)/(-c^2*x^2+1)^ 
(1/2))+6*arctanh(c*x)*polylog(2,(c*x+1)/(-c^2*x^2+1)^(1/2))+(c*x+1)*arctan 
h(c*x)+2*arctanh(c*x)*ln(1+(c*x+1)/(-c^2*x^2+1)^(1/2))+3/2*I*Pi*csgn(I/(1- 
(c*x+1)^2/(c^2*x^2-1)))*csgn(I*(-(c*x+1)^2/(c^2*x^2-1)-1))*csgn(I*(-(c*x+1 
)^2/(c^2*x^2-1)-1)/(1-(c*x+1)^2/(c^2*x^2-1)))*arctanh(c*x)^2-3/2*I*Pi*csgn 
(I/(1-(c*x+1)^2/(c^2*x^2-1)))*csgn(I*(-(c*x+1)^2/(c^2*x^2-1)-1)/(1-(c*x+1) 
^2/(c^2*x^2-1)))^2*arctanh(c*x)^2-3/2*I*Pi*csgn(I*(-(c*x+1)^2/(c^2*x^2-1)- 
1))*csgn(I*(-(c*x+1)^2/(c^2*x^2-1)-1)/(1-(c*x+1)^2/(c^2*x^2-1)))^2*arctanh 
(c*x)^2+3/2*I*Pi*csgn(I*(-(c*x+1)^2/(c^2*x^2-1)-1)/(1-(c*x+1)^2/(c^2*x^2-1 
)))^3*arctanh(c*x)^2)+2*d^3*a*b*c*(1/2*c^2*x^2*arctanh(c*x)+3*c*x*arcta...
 
3.1.89.5 Fricas [F]

\[ \int \frac {(d+c d x)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx=\int { \frac {{\left (c d x + d\right )}^{3} {\left (b \operatorname {artanh}\left (c x\right ) + a\right )}^{2}}{x^{2}} \,d x } \]

input
integrate((c*d*x+d)^3*(a+b*arctanh(c*x))^2/x^2,x, algorithm="fricas")
 
output
integral((a^2*c^3*d^3*x^3 + 3*a^2*c^2*d^3*x^2 + 3*a^2*c*d^3*x + a^2*d^3 + 
(b^2*c^3*d^3*x^3 + 3*b^2*c^2*d^3*x^2 + 3*b^2*c*d^3*x + b^2*d^3)*arctanh(c* 
x)^2 + 2*(a*b*c^3*d^3*x^3 + 3*a*b*c^2*d^3*x^2 + 3*a*b*c*d^3*x + a*b*d^3)*a 
rctanh(c*x))/x^2, x)
 
3.1.89.6 Sympy [F]

\[ \int \frac {(d+c d x)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx=d^{3} \left (\int 3 a^{2} c^{2}\, dx + \int \frac {a^{2}}{x^{2}}\, dx + \int \frac {3 a^{2} c}{x}\, dx + \int a^{2} c^{3} x\, dx + \int 3 b^{2} c^{2} \operatorname {atanh}^{2}{\left (c x \right )}\, dx + \int \frac {b^{2} \operatorname {atanh}^{2}{\left (c x \right )}}{x^{2}}\, dx + \int 6 a b c^{2} \operatorname {atanh}{\left (c x \right )}\, dx + \int \frac {2 a b \operatorname {atanh}{\left (c x \right )}}{x^{2}}\, dx + \int \frac {3 b^{2} c \operatorname {atanh}^{2}{\left (c x \right )}}{x}\, dx + \int b^{2} c^{3} x \operatorname {atanh}^{2}{\left (c x \right )}\, dx + \int \frac {6 a b c \operatorname {atanh}{\left (c x \right )}}{x}\, dx + \int 2 a b c^{3} x \operatorname {atanh}{\left (c x \right )}\, dx\right ) \]

input
integrate((c*d*x+d)**3*(a+b*atanh(c*x))**2/x**2,x)
 
output
d**3*(Integral(3*a**2*c**2, x) + Integral(a**2/x**2, x) + Integral(3*a**2* 
c/x, x) + Integral(a**2*c**3*x, x) + Integral(3*b**2*c**2*atanh(c*x)**2, x 
) + Integral(b**2*atanh(c*x)**2/x**2, x) + Integral(6*a*b*c**2*atanh(c*x), 
 x) + Integral(2*a*b*atanh(c*x)/x**2, x) + Integral(3*b**2*c*atanh(c*x)**2 
/x, x) + Integral(b**2*c**3*x*atanh(c*x)**2, x) + Integral(6*a*b*c*atanh(c 
*x)/x, x) + Integral(2*a*b*c**3*x*atanh(c*x), x))
 
3.1.89.7 Maxima [F]

\[ \int \frac {(d+c d x)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx=\int { \frac {{\left (c d x + d\right )}^{3} {\left (b \operatorname {artanh}\left (c x\right ) + a\right )}^{2}}{x^{2}} \,d x } \]

input
integrate((c*d*x+d)^3*(a+b*arctanh(c*x))^2/x^2,x, algorithm="maxima")
 
output
1/2*a^2*c^3*d^3*x^2 + 3*a^2*c^2*d^3*x + 3*(2*c*x*arctanh(c*x) + log(-c^2*x 
^2 + 1))*a*b*c*d^3 + 3*a^2*c*d^3*log(x) - (c*(log(c^2*x^2 - 1) - log(x^2)) 
 + 2*arctanh(c*x)/x)*a*b*d^3 - a^2*d^3/x + 1/8*(b^2*c^3*d^3*x^3 + 6*b^2*c^ 
2*d^3*x^2 - 2*b^2*d^3)*log(-c*x + 1)^2/x - integrate(-1/4*((b^2*c^4*d^3*x^ 
4 + 2*b^2*c^3*d^3*x^3 - 2*b^2*c*d^3*x - b^2*d^3)*log(c*x + 1)^2 + 4*(a*b*c 
^4*d^3*x^4 - a*b*c^3*d^3*x^3 + 3*a*b*c^2*d^3*x^2 - 3*a*b*c*d^3*x)*log(c*x 
+ 1) - (12*a*b*c^2*d^3*x^2 + (4*a*b*c^4*d^3 + b^2*c^4*d^3)*x^4 - 2*(2*a*b* 
c^3*d^3 - 3*b^2*c^3*d^3)*x^3 - 2*(6*a*b*c*d^3 + b^2*c*d^3)*x + 2*(b^2*c^4* 
d^3*x^4 + 2*b^2*c^3*d^3*x^3 - 2*b^2*c*d^3*x - b^2*d^3)*log(c*x + 1))*log(- 
c*x + 1))/(c*x^3 - x^2), x)
 
3.1.89.8 Giac [F]

\[ \int \frac {(d+c d x)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx=\int { \frac {{\left (c d x + d\right )}^{3} {\left (b \operatorname {artanh}\left (c x\right ) + a\right )}^{2}}{x^{2}} \,d x } \]

input
integrate((c*d*x+d)^3*(a+b*arctanh(c*x))^2/x^2,x, algorithm="giac")
 
output
integrate((c*d*x + d)^3*(b*arctanh(c*x) + a)^2/x^2, x)
 
3.1.89.9 Mupad [F(-1)]

Timed out. \[ \int \frac {(d+c d x)^3 (a+b \text {arctanh}(c x))^2}{x^2} \, dx=\int \frac {{\left (a+b\,\mathrm {atanh}\left (c\,x\right )\right )}^2\,{\left (d+c\,d\,x\right )}^3}{x^2} \,d x \]

input
int(((a + b*atanh(c*x))^2*(d + c*d*x)^3)/x^2,x)
 
output
int(((a + b*atanh(c*x))^2*(d + c*d*x)^3)/x^2, x)